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Worksheet generator
Pick what you want, print the page. The answer key comes with it, on its own sheet, and it tells you the mistake behind every wrong choice — not just which letter is right.
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1.Each shape stands for a whole number. A triangle plus a triangle plus a triangle is 12, and a triangle plus a square is 9. What is the square?[3]
A3
B4
C5
D6
E8
2.What is the remainder when 7 to the power 100 is divided by 5?[3]
A1
B2
C3
D4
E0
3.The two digits of a number are swapped and the number gets bigger by 36. Which of these could be the number?[4]
A13
B15
C24
D41
E62
4.What is 2 + 4 + 6 + ... + 100?[4]
A1275
B2450
C2500
D2550
E5100
5.The mean of four numbers is 9. Three of them are 5, 8 and 12. What is the fourth?[4]
A9
B10
C11
D12
E13
6.What is the units digit of 7 multiplied by itself 2026 times, that is 7 to the power 2026?[5]
Ait cannot be found without a calculator
B1
C3
D7
E9
7.The numbers 1 to 9 are placed in a row in some order. Can every neighbouring pair add up to an odd number?[5]
AYes, and many orders work
BYes, but only one order works
CNo, there are too many odd numbers
DNo, nine places is an odd number of places
EOnly if the row starts with an even number
8.A and B are different digits. The two-digit number AB added to the two-digit number BA gives 132. What is A + B?[5]
A3
B6
C11
D12
E13
9.How many two-digit numbers have both of their digits odd?[5]
A10
B20
C25
D45
E50
10.What is the last digit of 3 multiplied by itself 2026 times, that is, of 3 to the power 2026?[5]
A3
B9
C7
D1
E6
Math Kangaroo Star · https://kangaroo-atlas.vercel.app · seed 8 · CC BY-NC-SA 4.0 · Independent project, not affiliated with Math Kangaroo in USA, NFP.
Answer key — Math Kangaroo practice
Each wrong choice carries the thinking that produces it. When a student picks C, this is what they were doing.
1.C — 5KA-0061Operation puzzles and cryptarithms
AI solved for the triangle and gave that instead of the square.
BI found the triangle is 4 and gave that number, without going on to the second equation.
DI halved the 12 instead of dividing it by the three triangles.
EI subtracted the wrong way round, taking 9 from a number instead of taking the triangle from 9.
2.A — 1KA-0169Remainders and modular cycles
BI reduced 7 to 2 correctly but then used a remainder of 1 when dividing 100 by 4.
CI read the cycle backwards and landed on the entry before the right one.
DI used 100 divided by 4 giving 25 and read off the 25th entry as if the cycle had length 25.
EI assumed a power that large must be divisible by 5.
3.B — 15KA-0056Place value and digit positions
AI checked that the digits differ and stopped, without working out how much the swap actually changes the number.
CI saw a difference of 2 between the digits and expected that to give a change of 36.
DI ignored the direction: swapping this number makes it smaller, not bigger.
EI picked a number whose digits differ by 4 without noticing that the larger digit is already in front.
4.D — 2550KA-0058Clever regrouping (pair to round numbers)
AI found the sum of 1 to 50 and forgot that every term here is twice as big.
BI used 49 pairs instead of 25, losing one pair from the count.
CI estimated the answer as a round number rather than pairing properly.
EI paired the terms but forgot that pairing counts every number twice, so I never halved.
5.C — 11KA-0066Means, and working backwards from a mean
AI assumed the missing number must be the mean itself.
BI averaged the three known numbers instead of working from the total.
DI repeated one of the numbers already given rather than computing the missing one.
EI used a total of 37 instead of 36, adding the mean in once too often.
6.E — 9KA-0037Last-digit behavior of products and powers
AI assumed a number this large has no reachable last digit and gave up on the cycle.
BI found the cycle 7, 9, 3, 1 but used a remainder of 0 when the remainder is actually 2.
CI found the cycle but counted its positions starting at zero, shifting my answer along by one.
DI assumed the units digit of any power of 7 is always 7.
7.A — Yes, and many orders workKA-0049Parity of numbers (odd/even behavior)
BI found one arrangement that works and assumed a problem this fiddly could only have one answer.
CI saw five odd numbers against four even ones and called that a mismatch, when a row of nine needs exactly five of one and four of the other.
DI blamed the length of the row rather than checking how many odd and even numbers it has to hold.
EI decided the first number settles it without checking that starting even would need five even numbers, and only four exist.
8.D — 12KA-0060Operation puzzles and cryptarithms
AI added the digits of 132 instead of working out what A and B must be.
BI found A + B correctly and then halved it, as if the question wanted one digit.
CI spotted the 11 in the working and gave that instead of the sum it multiplies.
EI found a pair of digits by trial and misadded them by one.
9.C — 25KA-0135Digit-constraint puzzles
AI counted the odd numbers in one row of ten and treated that as the whole answer.
BI used four odd digits instead of five, forgetting that 9 is odd.
DI counted every two-digit number that is itself odd, which only fixes the last digit.
EI let the first digit be any of ten values rather than only the five odd ones.
10.B — 9KA-0158Last-digit behavior of products and powers
AI used the first entry of the cycle because 2026 is even, without working out where in the cycle it lands.
CI counted the cycle starting from zero, so a remainder of 2 put me one place too far along.
DI assumed a power that large must end in 1.
EI multiplied 3 by 2 and used the last digit of that.