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Worksheet generator
Pick what you want, print the page. The answer key comes with it, on its own sheet, and it tells you the mistake behind every wrong choice — not just which letter is right.
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1.Today is Tuesday. What day of the week will it be in 100 days?[3]
AMonday
BTuesday
CWednesday
DThursday
EFriday
2.One bus leaves every 12 minutes and another every 18 minutes. They leave together at 9:00. When do they next leave together?[3]
A9:06
B9:30
C9:36
D9:54
E12:36
3.In the number 4073, what is the value of the digit 7?[3]
A3
B7
C70
D700
E4000
4.What is 1 + 2 + 3 + ... + 20?[3]
A190
B200
C210
D220
E420
5.A tap drips about 3 times a minute. Roughly how many drips is that in one day?[3]
A180
B720
C1080
D4320
E43200
6.Each shape stands for a whole number. A triangle plus a triangle plus a triangle is 12, and a triangle plus a square is 9. What is the square?[3]
A3
B4
C5
D6
E8
7.A bread recipe uses flour and sugar in the ratio 5 to 3. The two together weigh 320 grams. How much of that is flour?[3]
A120 g
B160 g
C200 g
D192 g
E64 g
8.What is the remainder when 7 to the power 100 is divided by 5?[3]
A1
B2
C3
D4
E0
9.A price goes up by 20%, then down by 20%. Compared with the original price, the final price is:[4]
A20% lower
B4% lower
Cthe same
D4% higher
E40% higher
10.What is the units digit of 3 multiplied by itself 100 times, that is 3 to the power 100?[4]
A1
B3
C7
D9
Eit cannot be found without a calculator
Math Kangaroo Star · https://kangaroo-atlas.vercel.app · seed 6 · CC BY-NC-SA 4.0 · Independent project, not affiliated with Math Kangaroo in USA, NFP.
Answer key — Math Kangaroo practice
Each wrong choice carries the thinking that produces it. When a student picks C, this is what they were doing.
1.D — ThursdayKA-0021Remainders and modular cycles
AI found the remainder 2 but counted the two days starting from today rather than starting from tomorrow.
BI divided 100 by 7 and used the quotient of 14, treating the leftover days as if there were none.
CI remembered there was a remainder but used a remainder of 1 instead of working it out.
EI counted 100 divided by 7 as 14 remainder 3 instead of remainder 2.
2.C — 9:36KA-0041Factors, multiples, LCM and GCD by listing
AI found the greatest common divisor of 12 and 18 instead of the least common multiple.
BI added the two intervals together rather than looking for a time that is a multiple of both.
DI found a common multiple but not the least one, landing on a later coincidence.
EI multiplied the two intervals together instead of finding their least common multiple.
3.C — 70KA-0055Place value and digit positions
AI gave the last digit of the number instead of looking at the 7 at all.
BI gave the digit itself rather than what it is worth in the position it sits in.
DI counted the positions from the left, so I read the 7 as being in the hundreds place.
EI gave the value of the largest digit instead of the value of the 7.
4.C — 210KA-0057Clever regrouping (pair to round numbers)
AI paired the numbers from the outside in but left the 20 out of every pair, so I added only up to 19.
BI estimated the total as a round number instead of working it out.
DI used eleven pairs of 20 instead of ten pairs of 21.
EI multiplied 20 by 21 and forgot that pairing counts every number twice.
5.D — 4320KA-0059Estimation and order of magnitude
AI worked out the drips in an hour and stopped there.
BI multiplied by the 24 hours but forgot the 60 minutes in each one.
CI used 6 hours in a day, thinking of waking hours rather than a whole day.
EI used 600 minutes in an hour rather than 60.
6.C — 5KA-0061Operation puzzles and cryptarithms
AI solved for the triangle and gave that instead of the square.
BI found the triangle is 4 and gave that number, without going on to the second equation.
DI halved the 12 instead of dividing it by the three triangles.
EI subtracted the wrong way round, taking 9 from a number instead of taking the triangle from 9.
7.C — 200 gKA-0151Ratio as parts of a whole
AI worked out the part size correctly and then answered for the sugar instead of the flour.
BI split the 320 grams into two halves instead of into eight equal parts.
DI took three fifths of 320 rather than five eighths, using the ratio numbers as a fraction of each other.
EI divided 320 by the 5 in the ratio and stopped, treating 5 as the number of parts.
8.A — 1KA-0169Remainders and modular cycles
BI reduced 7 to 2 correctly but then used a remainder of 1 when dividing 100 by 4.
CI read the cycle backwards and landed on the entry before the right one.
DI used 100 divided by 4 giving 25 and read off the 25th entry as if the cycle had length 25.
EI assumed a power that large must be divisible by 5.
9.B — 4% lowerKA-0065Percentages and simple discounts
AI applied only the decrease and forgot that the price had already risen.
CI assumed a rise and a fall of the same percentage cancel each other out exactly.
DI got the size of the change right but the direction wrong.
EI added the two percentages together instead of applying them one after the other.
10.A — 1KA-0149Last-digit behavior of products and powers
BI assumed every power of 3 ends in 3.
CI found the cycle 3, 9, 7, 1 but counted its positions from zero, landing one step early.
DI used a remainder of 2 instead of 0 when dividing 100 by the cycle length of 4.
EI assumed a number this large has no reachable last digit, rather than looking for a repeat.